Hazel will be 90 years old in 20 years' time. Now, Marion's age is 45 of Hazel's age. What was Marion's age when she was 2 years more than 75% of Hazel's age?
| |
Marion |
Hazel |
Difference |
| Before |
3 p + 2 |
4 p |
1 p - 2 |
| Change 1 |
+ ? |
+ ? |
|
| After 1 (Now) |
4 u |
5 u |
1 u |
| Change 2 |
+ 20 |
+ 20 |
|
| After |
4 u + 20 |
90 |
|
Hazel's age in 20 years' time = 5 u + 20
5 u + 20 = 90
5 u = 90 - 20
5 u = 70
1 u = 70 ÷ 5 = 14
Difference between Hazel's age and Marion's age
= 1 u
= 14
75% =
75100 =
34 Difference in Hazel's age and Marion's age at first
= 4 p - (3 p + 2)
= 1 p - 2
The difference in age between Hazel and Marion remains unchanged.
1 p - 2 = 14
1 p = 14 + 2 = 16
Marion's age when she was 2 years more than 75% of Hazel's age
= 3 p + 2
= 3 x 16 + 2
= 48 + 2
= 50
Answer(s): 50
