Container H and Container J had 47 kg of pepper and 132.6 kg of pepper respectively. If 2 kg of pepper and 8.1 kg of pepper are added into Container H and Container J every day, how many days later will the pepper in Container H be one-third as much as the pepper in Container J?
| |
Make p the same
(1)x3 = (3) |
Container H
(1) |
Container J
(2) |
| Before |
141 |
47 |
132.6 |
| Change |
+ 6 u |
+ 2 u |
+ 8.1 u |
| After |
3 p |
1 p |
3 p |
47 + 2 u = 1 p --- (1)
132.6 + 8.1 u =
3 p --- (2)
Make p the same.
(1)
x3 = (3)
141 + 6 u =
3 p --- (3)
(2) = (3)
132.6 + 8.1 u = 141 + 6 u
8.1 u - 6 u = 141 - 132.6
2.1 u = 8.4
1 u = 8.4 ÷ 2.1 = 4
Time taken for the pepper in Container H to be one-third as much as the pepper in Container J = 4
Answer(s): 4
