Container Q and Container R had 50 kg of bread flour and 109.2 kg of bread flour respectively. If 2 kg of bread flour from Container Q and 6.3 kg of bread flour from Container R are used every day, how many days later will the bread flour in Container Q be half as much as the bread flour in Container R?
|
Make p the same (1)x2 = (3) |
Container Q (1) |
Container R (2) |
Before |
100 |
50 |
109.2 |
Change |
- 4 u |
- 2 u |
- 6.3 u |
After |
2 p |
1 p |
2 p |
50 - 2 u = 1 p --- (1)
109.2 - 6.3 u =
2 p --- (2)
Make p the same.
(1)
x2 = (3)
100 - 4 u =
2 p --- (3)
(2) = (3)
109.2 - 6.3 u = 100 - 4 u
6.3 u - 4 u = 109.2 - 100
2.3 u = 9.2
1 u = 9.2 ÷ 2.3 = 4
Time taken for the bread flour in Container Q to be half as much as the bread flour in Container R = 4
Answer(s): 4