Container Y and Container Z had 45 kg of pepper and 142.7 kg of pepper respectively. If 2 kg of pepper from Container Y and 7.1 kg of pepper from Container Z are used every day, how many days later will the pepper in Container Y be one-third as much as the pepper in Container Z?
| |
Make p the same
(1)x3 = (3) |
Container Y
(1) |
Container Z
(2) |
| Before |
135 |
45 |
142.7 |
| Change |
- 6 u |
- 2 u |
- 7.1 u |
| After |
3 p |
1 p |
3 p |
45 - 2 u = 1 p --- (1)
142.7 - 7.1 u =
3 p --- (2)
Make p the same.
(1)
x3 = (3)
135 - 6 u =
3 p --- (3)
(2) = (3)
142.7 - 7.1 u = 135 - 6 u
7.1 u - 6 u = 142.7 - 135
1.1 u = 7.7
1 u = 7.7 ÷ 1.1 = 7
Time taken for the pepper in Container Y to be one-third as much as the pepper in Container Z = 7
Answer(s): 7
