Container W and Container X had 49 kg of pepper and 158.7 kg of pepper respectively. If 2 kg of pepper from Container W and 7.3 kg of pepper from Container X are used every day, how many days later will the pepper in Container W be one-third as much as the pepper in Container X?
| |
Make p the same
(1)x3 = (3) |
Container W
(1) |
Container X
(2) |
| Before |
147 |
49 |
158.7 |
| Change |
- 6 u |
- 2 u |
- 7.3 u |
| After |
3 p |
1 p |
3 p |
49 - 2 u = 1 p --- (1)
158.7 - 7.3 u =
3 p --- (2)
Make p the same.
(1)
x3 = (3)
147 - 6 u =
3 p --- (3)
(2) = (3)
158.7 - 7.3 u = 147 - 6 u
7.3 u - 6 u = 158.7 - 147
1.3 u = 11.7
1 u = 11.7 ÷ 1.3 = 9
Time taken for the pepper in Container W to be one-third as much as the pepper in Container X = 9
Answer(s): 9
