Container L and Container M had 44 kg of pepper and 139.6 kg of pepper respectively. If 2 kg of pepper from Container L and 7.9 kg of pepper from Container M are used every day, how many days later will the pepper in Container L be one-third as much as the pepper in Container M?
| |
Make p the same
(1)x3 = (3) |
Container L
(1) |
Container M
(2) |
| Before |
132 |
44 |
139.6 |
| Change |
- 6 u |
- 2 u |
- 7.9 u |
| After |
3 p |
1 p |
3 p |
44 - 2 u = 1 p --- (1)
139.6 - 7.9 u =
3 p --- (2)
Make p the same.
(1)
x3 = (3)
132 - 6 u =
3 p --- (3)
(2) = (3)
139.6 - 7.9 u = 132 - 6 u
7.9 u - 6 u = 139.6 - 132
1.9 u = 7.6
1 u = 7.6 ÷ 1.9 = 4
Time taken for the pepper in Container L to be one-third as much as the pepper in Container M = 4
Answer(s): 4
