Container B and Container C had 39 kg of pepper and 111.8 kg of pepper respectively. If 2 kg of pepper and 7.3 kg of pepper are added into Container B and Container C every day, how many days later will the pepper in Container B be one-third as much as the pepper in Container C?
| |
Make p the same
(1)x3 = (3) |
Container B
(1) |
Container C
(2) |
| Before |
117 |
39 |
111.8 |
| Change |
+ 6 u |
+ 2 u |
+ 7.3 u |
| After |
3 p |
1 p |
3 p |
39 + 2 u = 1 p --- (1)
111.8 + 7.3 u =
3 p --- (2)
Make p the same.
(1)
x3 = (3)
117 + 6 u =
3 p --- (3)
(2) = (3)
111.8 + 7.3 u = 117 + 6 u
7.3 u - 6 u = 117 - 111.8
1.3 u = 5.2
1 u = 5.2 ÷ 1.3 = 4
Time taken for the pepper in Container B to be one-third as much as the pepper in Container C = 4
Answer(s): 4
