In a stationery kiosk, the number of folders was
89 of the total number of folders and glues together. Ben sold the folders and glues in sets of 3 folders and 5 glues. After selling all the glues, he still had 222 folders left. How many glues were in the stationery kiosk were sold?
| |
Folders |
Glues |
| Before |
8x5 =
40 u |
1x5 =
5 u |
| Change |
- 3x1 =
- 3 u |
- 5x1 =
- 5 u |
| After |
222 |
0 |
Since all the glues were sold, the number of glues at first and the number of glues sold were the same. Make the number of glues at first and sold the same. LCM of 1 and 5 is 5.
Number of folders sold
= 40 u - 3 u
= 37 u
37 u = 222
1 u = 222 ÷ 37 = 6
Number of glues were sold
= 5 u
= 5 x 6
= 30
Answer(s): 30
