In a stationery kiosk, the number of pencils was
89 of the total number of pencils and punchers together. Archie sold the pencils and punchers in sets of 2 pencils and 2 punchers. After selling all the punchers, he still had 84 pencils left. How many punchers were in the stationery kiosk were sold?
| |
Pencils |
Punchers |
| Before |
8x2 =
16 u |
1x2 =
2 u |
| Change |
- 2x1 =
- 2 u |
- 2x1 =
- 2 u |
| After |
84 |
0 |
Since all the punchers were sold, the number of punchers at first and the number of punchers sold were the same. Make the number of punchers at first and sold the same. LCM of 1 and 2 is 2.
Number of pencils sold
= 16 u - 2 u
= 14 u
14 u = 84
1 u = 84 ÷ 14 = 6
Number of punchers were sold
= 2 u
= 2 x 6
= 12
Answer(s): 12
