In a shop, the number of markers was
38 of the total number of markers and glues together. Howard sold the markers and glues in sets of 4 markers and 10 glues. After selling all the glues, he still had 16 markers left. How many markers were in the shop at first?
| |
Markers |
Glues |
| Before |
3x2 =
6 u |
5x2 =
10 u |
| Change |
- 4x1 =
- 4 u |
- 10x1 =
- 10 u |
| After |
16 |
0 |
Since all the glues were sold, the number of glues at first and the number of glues sold were the same. Make the number of glues at first and sold the same. LCM of 5 and 10 is 10.
Number of markers sold
= 6 u - 4 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
Number of markers at first
= 6 u
= 6 x 8
= 48
Answer(s): 48
