In a store, the number of correction tapes was
712 of the total number of correction tapes and pencils together. Pierre sold the correction tapes and pencils in sets of 1 correction tape and 6 pencils. After selling all the pencils, he still had 185 correction tapes left. How many pencils were in the store at first?
| |
Correction Tapes |
Pencils |
| Before |
7x6 =
42 u |
5x6 =
30 u |
| Change |
- 1x5 =
- 5 u |
- 6x5 =
- 30 u |
| After |
185 |
0 |
Since all the pencils were sold, the number of pencils at first and the number of pencils sold were the same. Make the number of pencils at first and sold the same. LCM of 5 and 6 is 30.
Number of correction tapes sold
= 42 u - 5 u
= 37 u
37 u = 185
1 u = 185 ÷ 37 = 5
Number of pencils at first
= 30 u
= 30 x 5
= 150
Answer(s): 150
