In a shop, the number of rulers was
57 of the total number of rulers and notebooks together. Justin sold the rulers and notebooks in sets of 2 rulers and 6 notebooks. After selling all the notebooks, he still had 52 rulers left. How many rulers were in the shop at first?
| |
Rulers |
Notebooks |
| Before |
5x3 =
15 u |
2x3 =
6 u |
| Change |
- 2x1 =
- 2 u |
- 6x1 =
- 6 u |
| After |
52 |
0 |
Since all the notebooks were sold, the number of notebooks at first and the number of notebooks sold were the same. Make the number of notebooks at first and sold the same. LCM of 2 and 6 is 6.
Number of rulers sold
= 15 u - 2 u
= 13 u
13 u = 52
1 u = 52 ÷ 13 = 4
Number of rulers at first
= 15 u
= 15 x 4
= 60
Answer(s): 60
