In a stationery kiosk, the number of highlighters was
57 of the total number of highlighters and rulers together. Neave sold the highlighters and rulers in sets of 2 highlighters and 5 rulers. After selling all the rulers, he still had 168 highlighters left. How many rulers were in the stationery kiosk were sold?
| |
Highlighters |
Rulers |
| Before |
5x5 =
25 u |
2x5 =
10 u |
| Change |
- 2x2 =
- 4 u |
- 5x2 =
- 10 u |
| After |
168 |
0 |
Since all the rulers were sold, the number of rulers at first and the number of rulers sold were the same. Make the number of rulers at first and sold the same. LCM of 2 and 5 is 10.
Number of highlighters sold
= 25 u - 4 u
= 21 u
21 u = 168
1 u = 168 ÷ 21 = 8
Number of rulers were sold
= 10 u
= 10 x 8
= 80
Answer(s): 80
