In a stationery kiosk, the number of pencils was
23 of the total number of pencils and highlighters together. Peter sold the pencils and highlighters in sets of 2 pencils and 3 highlighters. After selling all the highlighters, he still had 28 pencils left. How many pencils were in the stationery kiosk at first?
| |
Pencils |
Highlighters |
| Before |
2x3 =
6 u |
1x3 =
3 u |
| Change |
- 2x1 =
- 2 u |
- 3x1 =
- 3 u |
| After |
28 |
0 |
Since all the highlighters were sold, the number of highlighters at first and the number of highlighters sold were the same. Make the number of highlighters at first and sold the same. LCM of 1 and 3 is 3.
Number of pencils sold
= 6 u - 2 u
= 4 u
4 u = 28
1 u = 28 ÷ 4 = 7
Number of pencils at first
= 6 u
= 6 x 7
= 42
Answer(s): 42
