In a store, the number of rulers was
29 of the total number of rulers and markers together. Fred sold the rulers and markers in sets of 1 ruler and 5 markers. After selling all the markers, he still had 9 rulers left. How many markers were in the store at first?
|
Rulers |
Markers |
Before |
2x5 = 10 u |
7x5 = 35 u |
Change |
- 1x7 = - 7 u |
- 5x7 = - 35 u |
After |
9 |
0 |
Since all the markers were sold, the number of markers at first and the number of markers sold were the same. Make the number of markers at first and sold the same. LCM of 7 and 5 is 35.
Number of rulers sold
= 10 u - 7 u
= 3 u
3 u = 9
1 u = 9 ÷ 3 = 3
Number of markers at first
= 35 u
= 35 x 3
= 105
Answer(s): 105