In a stationery shop, the number of rulers was
67 of the total number of rulers and punchers together. Luke sold the rulers and punchers in sets of 2 rulers and 2 punchers. After selling all the punchers, he still had 110 rulers left. How many rulers were in the stationery shop at first?
| |
Rulers |
Punchers |
| Before |
6x2 =
12 u |
1x2 =
2 u |
| Change |
- 2x1 =
- 2 u |
- 2x1 =
- 2 u |
| After |
110 |
0 |
Since all the punchers were sold, the number of punchers at first and the number of punchers sold were the same. Make the number of punchers at first and sold the same. LCM of 1 and 2 is 2.
Number of rulers sold
= 12 u - 2 u
= 10 u
10 u = 110
1 u = 110 ÷ 10 = 11
Number of rulers at first
= 12 u
= 12 x 11
= 132
Answer(s): 132
