In a book shop, the number of correction tapes was
67 of the total number of correction tapes and foolscaps together. Justin sold the correction tapes and foolscaps in sets of 1 correction tape and 6 foolscaps. After selling all the foolscaps, he still had 385 correction tapes left. How many foolscaps were in the book shop at first?
| |
Correction Tapes |
Foolscaps |
| Before |
6x6 =
36 u |
1x6 =
6 u |
| Change |
- 1x1 =
- 1 u |
- 6x1 =
- 6 u |
| After |
385 |
0 |
Since all the foolscaps were sold, the number of foolscaps at first and the number of foolscaps sold were the same. Make the number of foolscaps at first and sold the same. LCM of 1 and 6 is 6.
Number of correction tapes sold
= 36 u - 1 u
= 35 u
35 u = 385
1 u = 385 ÷ 35 = 11
Number of foolscaps at first
= 6 u
= 6 x 11
= 66
Answer(s): 66
