In a stationery shop, the number of punchers was
59 of the total number of punchers and markers together. Pierre sold the punchers and markers in sets of 4 punchers and 10 markers. After selling all the markers, he still had 102 punchers left. How many punchers were in the stationery shop at first?
|
Punchers |
Markers |
Before |
5x5 = 25 u |
4x5 = 20 u |
Change |
- 4x2 = - 8 u |
- 10x2 = - 20 u |
After |
102 |
0 |
Since all the markers were sold, the number of markers at first and the number of markers sold were the same. Make the number of markers at first and sold the same. LCM of 4 and 10 is 20.
Number of punchers sold
= 25 u - 8 u
= 17 u
17 u = 102
1 u = 102 ÷ 17 = 6
Number of punchers at first
= 25 u
= 25 x 6
= 150
Answer(s): 150