In a factory, Machine A was turned on first and it produced 192 fishballs. Then Machine A and Machine B were turned on at the same time to continue production. For every 4 fishballs Machine A produced, Machine B produced 6 fishballs. Machine B produced 52 less than
37 of the total number of fishballs produced. How many fishballs were produced altogether?
|
Make u the same (1) x 3 = (3) |
Machine A (1) |
Machine B (2) |
Make u the same (2) x 2 = (4) |
Total |
Before |
576 |
192 |
0 |
0 |
|
Change |
+ 12 u |
+ 4 u |
+ 6 u |
+ 12 u |
|
After |
9 p + 156 |
3 p + 52 |
3 p - 52 |
6 p - 104 |
7 p |
From (3)
576 + 12 u = 9 p + 156
12 u = 9 p + 156 - 576
12 u = 9 p - 420
From (4)
0 + 12 u = 6 p - 104
12 u = 6 p - 104
(3) = (4)
9 p - 420 = 6 p - 104
9 p - 6 p = 420 - 104
3 p = 316
Number of fishballs that were produced altogether
= 7 p
= 7 x 316
= 2212
Answer(s): 2212