In a factory, Machine A was turned on first and it produced 155 fishballs. Then Machine A and Machine B were turned on at the same time to continue production. For every 4 fishballs Machine A produced, Machine B produced 5 fishballs. Machine B produced 54 less than
15 of the total number of fishballs produced. How many fishballs were produced altogether?
|
Make u the same (1) x 5 = (3) |
Machine A (1) |
Machine B (2) |
Make u the same (2) x 4 = (4) |
Total |
Before |
775 |
155 |
0 |
0 |
|
Change |
+ 20 u |
+ 4 u |
+ 5 u |
+ 20 u |
|
After |
5 p + 270 |
1 p + 54 |
1 p - 54 |
4 p - 216 |
5 p |
From (3)
775 + 20 u = 5 p + 270
20 u = 5 p + 270 - 775
20 u = 5 p - 505
From (4)
0 + 20 u = 4 p - 216
20 u = 4 p - 216
(3) = (4)
5 p - 505 = 4 p - 216
5 p - 4 p = 505 - 216
1 p = 289
Number of fishballs that were produced altogether
= 5 p
= 5 x 289
= 1445
Answer(s): 1445