In a factory, Machine A was turned on first and it produced 288 wontons. Then Machine A and Machine B were turned on at the same time to continue production. For every 4 wontons Machine A produced, Machine B produced 5 wontons. Machine B produced 58 less than
13 of the total number of wontons produced. How many wontons were produced altogether?
|
Make u the same (1) x 5 = (3) |
Machine A (1) |
Machine B (2) |
Make u the same (2) x 4 = (4) |
Total |
Before |
1440 |
288 |
0 |
0 |
|
Change |
+ 20 u |
+ 4 u |
+ 5 u |
+ 20 u |
|
After |
5 p + 290 |
1 p + 58 |
1 p - 58 |
4 p - 232 |
3 p |
From (3)
1440 + 20 u = 5 p + 290
20 u = 5 p + 290 - 1440
20 u = 5 p - 1150
From (4)
0 + 20 u = 4 p - 232
20 u = 4 p - 232
(3) = (4)
5 p - 1150 = 4 p - 232
5 p - 4 p = 1150 - 232
1 p = 918
Number of wontons that were produced altogether
= 3 p
= 3 x 918
= 2754
Answer(s): 2754