In a factory, Machine A was turned on first and it produced 240 fishballs. Then Machine A and Machine B were turned on at the same time to continue production. For every 4 fishballs Machine A produced, Machine B produced 6 fishballs. Machine B produced 40 less than
25 of the total number of fishballs produced. How many fishballs were produced altogether?
|
Make u the same (1) x 3 = (3) |
Machine A (1) |
Machine B (2) |
Make u the same (2) x 2 = (4) |
Total |
Before |
720 |
240 |
0 |
0 |
|
Change |
+ 12 u |
+ 4 u |
+ 6 u |
+ 12 u |
|
After |
6 p + 120 |
2 p + 40 |
2 p - 40 |
4 p - 80 |
5 p |
From (3)
720 + 12 u = 6 p + 120
12 u = 6 p + 120 - 720
12 u = 6 p - 600
From (4)
0 + 12 u = 4 p - 80
12 u = 4 p - 80
(3) = (4)
6 p - 600 = 4 p - 80
6 p - 4 p = 600 - 80
2 p = 520
Number of fishballs that were produced altogether
= 5 p
= 5 x 520
= 2600
Answer(s): 2600