In a factory, Machine A was turned on first and it produced 204 dumplings. Then Machine A and Machine B were turned on at the same time to continue production. For every 3 dumplings Machine A produced, Machine B produced 5 dumplings. Machine B produced 28 less than
15 of the total number of dumplings produced. How many dumplings were produced altogether?
|
Make u the same (1) x 5 = (3) |
Machine A (1) |
Machine B (2) |
Make u the same (2) x 3 = (4) |
Total |
Before |
1020 |
204 |
0 |
0 |
|
Change |
+ 15 u |
+ 3 u |
+ 5 u |
+ 15 u |
|
After |
5 p + 140 |
1 p + 28 |
1 p - 28 |
3 p - 84 |
5 p |
From (3)
1020 + 15 u = 5 p + 140
15 u = 5 p + 140 - 1020
15 u = 5 p - 880
From (4)
0 + 15 u = 3 p - 84
15 u = 3 p - 84
(3) = (4)
5 p - 880 = 3 p - 84
5 p - 3 p = 880 - 84
2 p = 796
Number of dumplings that were produced altogether
= 5 p
= 5 x 796
= 3980
Answer(s): 3980