In a factory, Machine A was turned on first and it produced 217 fishballs. Then Machine A and Machine B were turned on at the same time to continue production. For every 4 fishballs Machine A produced, Machine B produced 5 fishballs. Machine B produced 61 less than
15 of the total number of fishballs produced. How many fishballs were produced altogether?
|
Make u the same (1) x 5 = (3) |
Machine A (1) |
Machine B (2) |
Make u the same (2) x 4 = (4) |
Total |
Before |
1085 |
217 |
0 |
0 |
|
Change |
+ 20 u |
+ 4 u |
+ 5 u |
+ 20 u |
|
After |
5 p + 305 |
1 p + 61 |
1 p - 61 |
4 p - 244 |
5 p |
From (3)
1085 + 20 u = 5 p + 305
20 u = 5 p + 305 - 1085
20 u = 5 p - 780
From (4)
0 + 20 u = 4 p - 244
20 u = 4 p - 244
(3) = (4)
5 p - 780 = 4 p - 244
5 p - 4 p = 780 - 244
1 p = 536
Number of fishballs that were produced altogether
= 5 p
= 5 x 536
= 2680
Answer(s): 2680