In a factory, Machine A was turned on first and it produced 105 dumplings. Then Machine A and Machine B were turned on at the same time to continue production. For every 3 dumplings Machine A produced, Machine B produced 5 dumplings. Machine B produced 48 less than
37 of the total number of dumplings produced. How many dumplings were produced altogether?
| |
Make u the same
(1) x 5 = (3) |
Machine A
(1) |
Machine B
(2) |
Make u the same
(2) x 3 = (4) |
Total |
| Before |
525 |
105 |
0 |
0 |
|
| Change |
+ 15 u |
+ 3 u |
+ 5 u |
+ 15 u |
|
| After |
15 p + 240 |
3 p + 48 |
3 p - 48 |
9 p - 144 |
7 p |
From (3)
525 + 15 u = 15 p + 240
15 u = 15 p + 240 - 525
15 u = 15 p - 285
From (4)
0 + 15 u = 9 p - 144
15 u = 9 p - 144
(3) = (4)
15 p - 285 = 9 p - 144
15 p - 9 p = 285 - 144
6 p = 141
Number of dumplings that were produced altogether
= 7 p
= 7 x 141
= 987
Answer(s): 987
