In a factory, Machine A was turned on first and it produced 222 fishballs. Then Machine A and Machine B were turned on at the same time to continue production. For every 4 fishballs Machine A produced, Machine B produced 5 fishballs. Machine B produced 47 less than
35 of the total number of fishballs produced. How many fishballs were produced altogether?
|
Make u the same (1) x 5 = (3) |
Machine A (1) |
Machine B (2) |
Make u the same (2) x 4 = (4) |
Total |
Before |
1110 |
222 |
0 |
0 |
|
Change |
+ 20 u |
+ 4 u |
+ 5 u |
+ 20 u |
|
After |
15 p + 235 |
3 p + 47 |
3 p - 47 |
12 p - 188 |
5 p |
From (3)
1110 + 20 u = 15 p + 235
20 u = 15 p + 235 - 1110
20 u = 15 p - 875
From (4)
0 + 20 u = 12 p - 188
20 u = 12 p - 188
(3) = (4)
15 p - 875 = 12 p - 188
15 p - 12 p = 875 - 188
3 p = 687
Number of fishballs that were produced altogether
= 5 p
= 5 x 687
= 3435
Answer(s): 3435