In a factory, Machine A was turned on first and it produced 150 fishballs. Then Machine A and Machine B were turned on at the same time to continue production. For every 4 fishballs Machine A produced, Machine B produced 5 fishballs. Machine B produced 66 less than
12 of the total number of fishballs produced. How many fishballs were produced altogether?
|
Make u the same (1) x 5 = (3) |
Machine A (1) |
Machine B (2) |
Make u the same (2) x 4 = (4) |
Total |
Before |
750 |
150 |
0 |
0 |
|
Change |
+ 20 u |
+ 4 u |
+ 5 u |
+ 20 u |
|
After |
5 p + 330 |
1 p + 66 |
1 p - 66 |
4 p - 264 |
2 p |
From (3)
750 + 20 u = 5 p + 330
20 u = 5 p + 330 - 750
20 u = 5 p - 420
From (4)
0 + 20 u = 4 p - 264
20 u = 4 p - 264
(3) = (4)
5 p - 420 = 4 p - 264
5 p - 4 p = 420 - 264
1 p = 156
Number of fishballs that were produced altogether
= 2 p
= 2 x 156
= 312
Answer(s): 312