In a factory, Machine A was turned on first and it produced 144 dumplings. Then Machine A and Machine B were turned on at the same time to continue production. For every 3 dumplings Machine A produced, Machine B produced 6 dumplings. Machine B produced 20 less than
37 of the total number of dumplings produced. How many dumplings were produced altogether?
|
Make u the same (1) x 2 = (3) |
Machine A (1) |
Machine B (2) |
Make u the same (2) x 1 = (4) |
Total |
Before |
288 |
144 |
0 |
0 |
|
Change |
+ 6 u |
+ 3 u |
+ 6 u |
+ 6 u |
|
After |
6 p + 40 |
3 p + 20 |
3 p - 20 |
3 p - 20 |
7 p |
From (3)
288 + 6 u = 6 p + 40
6 u = 6 p + 40 - 288
6 u = 6 p - 248
From (4)
0 + 6 u = 3 p - 20
6 u = 3 p - 20
(3) = (4)
6 p - 248 = 3 p - 20
6 p - 3 p = 248 - 20
3 p = 228
Number of dumplings that were produced altogether
= 7 p
= 7 x 228
= 1596
Answer(s): 1596