At the stadium were some adults.
12 of the number of locals was equal to 2 times the number of tourists. When another 22 tourists entered and 80 locals left, the ratio of the number of locals to the number of tourists become 8 : 5. Find the number of tourists at the stadium at first.
| |
Make p the same
(1)x5 = (3) |
Locals
(1) |
Tourists
(2) |
Make p the same
(2)x8 = (4) |
| Before |
20 u |
4 u |
1 u |
8 u |
| Change |
- 400 |
- 80 |
+ 22 |
+ 176 |
| After |
40 p |
8 p |
5 p |
40 p |
12 of the locals = 2 times of the tourists
1x22x2 of the locals =
2x11x1 of the tourists
Make the numerators the same. LCM of 1 and 2 is 2.
24 of the locals =
21 of the tourists
Locals : Tourists = 4 : 1
Make p the same.
(3) = (4)
20 u - 400 = 8 u + 176
20 u - 8 u = 176 + 400
12 u = 576
1 u = 576 ÷ 12 = 48
Number of tourists at the stadium at first
= 1 u
= 48
Answer(s): 48
