Liam and Ken had 148 pencils together. Liam had 28 more pencils than Ken. Both of them sold some of their pencils. Ken sold 30% less pencils than what Liam sold. In the end, Ken had half as many pencils left as Liam. How many pencils had Liam left?
| |
Liam
(1) |
Ken
(2) |
Make p the same
(2)x2 = (3) |
Comparing Liam
and Ken at first |
28 more |
|
|
| Before |
88 |
60 |
120 |
| Change |
- 10 u |
- 7 u |
- 14 u |
| After |
2 p |
1 p |
2 p |
Number of pencils that Ken had at first
= (148 - 28) ÷ 2
= 120 ÷ 2
= 60
Number of pencils that Liam had at first
= 60 + 28
= 88
Number of pencils that Ken sold in percent
= 100% - 30%
= 70%
70% =
70100 =
710 Make p the same.
(1) = (3)
88 - 10 u = 120 - 14 u
14 u - 10 u = 120 - 88
4 u = 32
1 u = 32 ÷ 4 = 8
Number of pencils that Liam had left
= 88 - 10 u
= 88 - 10 x 8
= 88 - 80
= 8
Answer(s): 8
