Mark and Reggie had 54 markers together. Mark had 12 more markers than Reggie. Both of them sold some of their markers. Reggie sold 20% less markers than what Mark sold. In the end, Reggie had half as many markers left as Mark. How many markers had Mark left?
| |
Mark
(1) |
Reggie
(2) |
Make p the same
(2)x2 = (3) |
Comparing Mark
and Reggie at first |
12 more |
|
|
| Before |
33 |
21 |
42 |
| Change |
- 5 u |
- 4 u |
- 8 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Reggie had at first
= (54 - 12) ÷ 2
= 42 ÷ 2
= 21
Number of markers that Mark had at first
= 21 + 12
= 33
Number of markers that Reggie sold in percent
= 100% - 20%
= 80%
80% =
80100 =
45 Make p the same.
(1) = (3)
33 - 5 u = 42 - 8 u
8 u - 5 u = 42 - 33
3 u = 9
1 u = 9 ÷ 3 = 3
Number of markers that Mark had left
= 33 - 5 u
= 33 - 5 x 3
= 33 - 15
= 18
Answer(s): 18
