Perry and Paul had 54 markers together. Paul had 2 less markers than Perry. Both of them sold some of their markers. Paul sold 25% more markers than what Perry sold. In the end, Paul had half as many markers left as Perry. How many markers had Paul left?
| |
Perry
(1) |
Paul
(2) |
Make p the same
(2)x2 = (3) |
Comparing Perry
and Paul at first |
2 more |
|
|
| Before |
28 |
26 |
52 |
| Change |
- 4 u |
- 5 u |
- 10 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Paul had at first
= (54 - 2) ÷ 2
= 52 ÷ 2
= 26
Number of markers that Perry had at first
= 26 + 2
= 28
Number of markers that Paul sold in percent
= 100% + 25%
= 125%
125% =
125100 =
54 Make p the same.
(1) = (3)
28 - 4 u = 52 - 10 u
10 u - 4 u = 52 - 28
6 u = 24
1 u = 24 ÷ 6 = 4
Number of markers that Paul had left
= 26 - 5 u
= 26 - 5 x 4
= 26 - 20
= 6
Answer(s): 6
