Henry and Rael had 177 pens together. Rael had 3 less pens than Henry. Both of them sold some of their pens. Rael sold 10% more pens than what Henry sold. In the end, Rael had half as many pens left as Henry. How many pens had Rael left?
| |
Henry
(1) |
Rael
(2) |
Make p the same
(2)x2 = (3) |
Comparing Henry
and Rael at first |
3 more |
|
|
| Before |
90 |
87 |
174 |
| Change |
- 10 u |
- 11 u |
- 22 u |
| After |
2 p |
1 p |
2 p |
Number of pens that Rael had at first
= (177 - 3) ÷ 2
= 174 ÷ 2
= 87
Number of pens that Henry had at first
= 87 + 3
= 90
Number of pens that Rael sold in percent
= 100% + 10%
= 110%
110% =
110100 =
1110 Make p the same.
(1) = (3)
90 - 10 u = 174 - 22 u
22 u - 10 u = 174 - 90
12 u = 84
1 u = 84 ÷ 12 = 7
Number of pens that Rael had left
= 87 - 11 u
= 87 - 11 x 7
= 87 - 77
= 10
Answer(s): 10
