Sam and Sean had 196 markers together. Sam had 12 more markers than Sean. Both of them sold some of their markers. Sean sold 10% less markers than what Sam sold. In the end, Sean had half as many markers left as Sam. How many markers had Sam left?
| |
Sam
(1) |
Sean
(2) |
Make p the same
(2)x2 = (3) |
Comparing Sam
and Sean at first |
12 more |
|
|
| Before |
104 |
92 |
184 |
| Change |
- 10 u |
- 9 u |
- 18 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Sean had at first
= (196 - 12) ÷ 2
= 184 ÷ 2
= 92
Number of markers that Sam had at first
= 92 + 12
= 104
Number of markers that Sean sold in percent
= 100% - 10%
= 90%
90% =
90100 =
910 Make p the same.
(1) = (3)
104 - 10 u = 184 - 18 u
18 u - 10 u = 184 - 104
8 u = 80
1 u = 80 ÷ 8 = 10
Number of markers that Sam had left
= 104 - 10 u
= 104 - 10 x 10
= 104 - 100
= 4
Answer(s): 4
