Vaidev and Caden had 183 notebooks together. Caden had 5 less notebooks than Vaidev. Both of them sold some of their notebooks. Caden sold 10% more notebooks than what Vaidev sold. In the end, Caden had half as many notebooks left as Vaidev. How many notebooks had Caden left?
|
Vaidev (1) |
Caden (2) |
Make p the same (2)x2 = (3) |
Comparing Vaidev and Caden at first |
5 more |
|
|
Before |
94 |
89 |
178 |
Change |
- 10 u |
- 11 u |
- 22 u |
After |
2 p |
1 p |
2 p |
Number of notebooks that Caden had at first
= (183 - 5) ÷ 2
= 178 ÷ 2
= 89
Number of notebooks that Vaidev had at first
= 89 + 5
= 94
Number of notebooks that Caden sold in percent
= 100% + 10%
= 110%
110% =
110100 =
1110 Make p the same.
(1) = (3)
94 - 10 u = 178 - 22 u
22 u - 10 u = 178 - 94
12 u = 84
1 u = 84 ÷ 12 = 7
Number of notebooks that Caden had left
= 89 - 11 u
= 89 - 11 x 7
= 89 - 77
= 12
Answer(s): 12