Warren and Jenson had 99 markers together. Warren had 21 more markers than Jenson. Both of them sold some of their markers. Jenson sold 25% less markers than what Warren sold. In the end, Jenson had half as many markers left as Warren. How many markers had Warren left?
| |
Warren
(1) |
Jenson
(2) |
Make p the same
(2)x2 = (3) |
Comparing Warren
and Jenson at first |
21 more |
|
|
| Before |
60 |
39 |
78 |
| Change |
- 4 u |
- 3 u |
- 6 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Jenson had at first
= (99 - 21) ÷ 2
= 78 ÷ 2
= 39
Number of markers that Warren had at first
= 39 + 21
= 60
Number of markers that Jenson sold in percent
= 100% - 25%
= 75%
75% =
75100 =
34 Make p the same.
(1) = (3)
60 - 4 u = 78 - 6 u
6 u - 4 u = 78 - 60
2 u = 18
1 u = 18 ÷ 2 = 9
Number of markers that Warren had left
= 60 - 4 u
= 60 - 4 x 9
= 60 - 36
= 24
Answer(s): 24
