Liam and Archie had 93 markers together. Archie had 3 less markers than Liam. Both of them sold some of their markers. Archie sold 25% more markers than what Liam sold. In the end, Archie had half as many markers left as Liam. How many markers had Archie left?
| |
Liam
(1) |
Archie
(2) |
Make p the same
(2)x2 = (3) |
Comparing Liam
and Archie at first |
3 more |
|
|
| Before |
48 |
45 |
90 |
| Change |
- 4 u |
- 5 u |
- 10 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Archie had at first
= (93 - 3) ÷ 2
= 90 ÷ 2
= 45
Number of markers that Liam had at first
= 45 + 3
= 48
Number of markers that Archie sold in percent
= 100% + 25%
= 125%
125% =
125100 =
54 Make p the same.
(1) = (3)
48 - 4 u = 90 - 10 u
10 u - 4 u = 90 - 48
6 u = 42
1 u = 42 ÷ 6 = 7
Number of markers that Archie had left
= 45 - 5 u
= 45 - 5 x 7
= 45 - 35
= 10
Answer(s): 10
