Charlie and Dylan had 85 pencils together. Dylan had 5 less pencils than Charlie. Both of them sold some of their pencils. Dylan sold 20% more pencils than what Charlie sold. In the end, Dylan had half as many pencils left as Charlie. How many pencils had Dylan left?
| |
Charlie
(1) |
Dylan
(2) |
Make p the same
(2)x2 = (3) |
Comparing Charlie
and Dylan at first |
5 more |
|
|
| Before |
45 |
40 |
80 |
| Change |
- 5 u |
- 6 u |
- 12 u |
| After |
2 p |
1 p |
2 p |
Number of pencils that Dylan had at first
= (85 - 5) ÷ 2
= 80 ÷ 2
= 40
Number of pencils that Charlie had at first
= 40 + 5
= 45
Number of pencils that Dylan sold in percent
= 100% + 20%
= 120%
120% =
120100 =
65 Make p the same.
(1) = (3)
45 - 5 u = 80 - 12 u
12 u - 5 u = 80 - 45
7 u = 35
1 u = 35 ÷ 7 = 5
Number of pencils that Dylan had left
= 40 - 6 u
= 40 - 6 x 5
= 40 - 30
= 10
Answer(s): 10
