Luis and Valen had 84 markers together. Luis had 16 more markers than Valen. Both of them sold some of their markers. Valen sold 20% less markers than what Luis sold. In the end, Valen had half as many markers left as Luis. How many markers had Luis left?
| |
Luis
(1) |
Valen
(2) |
Make p the same
(2)x2 = (3) |
Comparing Luis
and Valen at first |
16 more |
|
|
| Before |
50 |
34 |
68 |
| Change |
- 5 u |
- 4 u |
- 8 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Valen had at first
= (84 - 16) ÷ 2
= 68 ÷ 2
= 34
Number of markers that Luis had at first
= 34 + 16
= 50
Number of markers that Valen sold in percent
= 100% - 20%
= 80%
80% =
80100 =
45 Make p the same.
(1) = (3)
50 - 5 u = 68 - 8 u
8 u - 5 u = 68 - 50
3 u = 18
1 u = 18 ÷ 3 = 6
Number of markers that Luis had left
= 50 - 5 u
= 50 - 5 x 6
= 50 - 30
= 20
Answer(s): 20
