Fred and Zane had 233 markers together. Fred had 19 more markers than Zane. Both of them sold some of their markers. Zane sold 10% less markers than what Fred sold. In the end, Zane had half as many markers left as Fred. How many markers had Fred left?
| |
Fred
(1) |
Zane
(2) |
Make p the same
(2)x2 = (3) |
Comparing Fred
and Zane at first |
19 more |
|
|
| Before |
126 |
107 |
214 |
| Change |
- 10 u |
- 9 u |
- 18 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Zane had at first
= (233 - 19) ÷ 2
= 214 ÷ 2
= 107
Number of markers that Fred had at first
= 107 + 19
= 126
Number of markers that Zane sold in percent
= 100% - 10%
= 90%
90% =
90100 =
910 Make p the same.
(1) = (3)
126 - 10 u = 214 - 18 u
18 u - 10 u = 214 - 126
8 u = 88
1 u = 88 ÷ 8 = 11
Number of markers that Fred had left
= 126 - 10 u
= 126 - 10 x 11
= 126 - 110
= 16
Answer(s): 16
