Fred and Will had 114 pencils together. Will had 2 less pencils than Fred. Both of them sold some of their pencils. Will sold 25% more pencils than what Fred sold. In the end, Will had half as many pencils left as Fred. How many pencils had Will left?
| |
Fred
(1) |
Will
(2) |
Make p the same
(2)x2 = (3) |
Comparing Fred
and Will at first |
2 more |
|
|
| Before |
58 |
56 |
112 |
| Change |
- 4 u |
- 5 u |
- 10 u |
| After |
2 p |
1 p |
2 p |
Number of pencils that Will had at first
= (114 - 2) ÷ 2
= 112 ÷ 2
= 56
Number of pencils that Fred had at first
= 56 + 2
= 58
Number of pencils that Will sold in percent
= 100% + 25%
= 125%
125% =
125100 =
54 Make p the same.
(1) = (3)
58 - 4 u = 112 - 10 u
10 u - 4 u = 112 - 58
6 u = 54
1 u = 54 ÷ 6 = 9
Number of pencils that Will had left
= 56 - 5 u
= 56 - 5 x 9
= 56 - 45
= 11
Answer(s): 11
