Albert and Japheth had 234 pens together. Albert had 46 more pens than Japheth. Both of them sold some of their pens. Japheth sold 30% less pens than what Albert sold. In the end, Japheth had half as many pens left as Albert. How many pens had Albert left?
| |
Albert
(1) |
Japheth
(2) |
Make p the same
(2)x2 = (3) |
Comparing Albert
and Japheth at first |
46 more |
|
|
| Before |
140 |
94 |
188 |
| Change |
- 10 u |
- 7 u |
- 14 u |
| After |
2 p |
1 p |
2 p |
Number of pens that Japheth had at first
= (234 - 46) ÷ 2
= 188 ÷ 2
= 94
Number of pens that Albert had at first
= 94 + 46
= 140
Number of pens that Japheth sold in percent
= 100% - 30%
= 70%
70% =
70100 =
710 Make p the same.
(1) = (3)
140 - 10 u = 188 - 14 u
14 u - 10 u = 188 - 140
4 u = 48
1 u = 48 ÷ 4 = 12
Number of pens that Albert had left
= 140 - 10 u
= 140 - 10 x 12
= 140 - 120
= 20
Answer(s): 20
