Luke and Sean had 201 notebooks together. Sean had 3 less notebooks than Luke. Both of them sold some of their notebooks. Sean sold 10% more notebooks than what Luke sold. In the end, Sean had half as many notebooks left as Luke. How many notebooks had Sean left?
| |
Luke
(1) |
Sean
(2) |
Make p the same
(2)x2 = (3) |
Comparing Luke
and Sean at first |
3 more |
|
|
| Before |
102 |
99 |
198 |
| Change |
- 10 u |
- 11 u |
- 22 u |
| After |
2 p |
1 p |
2 p |
Number of notebooks that Sean had at first
= (201 - 3) ÷ 2
= 198 ÷ 2
= 99
Number of notebooks that Luke had at first
= 99 + 3
= 102
Number of notebooks that Sean sold in percent
= 100% + 10%
= 110%
110% =
110100 =
1110 Make p the same.
(1) = (3)
102 - 10 u = 198 - 22 u
22 u - 10 u = 198 - 102
12 u = 96
1 u = 96 ÷ 12 = 8
Number of notebooks that Sean had left
= 99 - 11 u
= 99 - 11 x 8
= 99 - 88
= 11
Answer(s): 11
