Julian and Wesley had 107 markers together. Julian had 9 more markers than Wesley. Both of them sold some of their markers. Wesley sold 10% less markers than what Julian sold. In the end, Wesley had half as many markers left as Julian. How many markers had Julian left?
| |
Julian
(1) |
Wesley
(2) |
Make p the same
(2)x2 = (3) |
Comparing Julian
and Wesley at first |
9 more |
|
|
| Before |
58 |
49 |
98 |
| Change |
- 10 u |
- 9 u |
- 18 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Wesley had at first
= (107 - 9) ÷ 2
= 98 ÷ 2
= 49
Number of markers that Julian had at first
= 49 + 9
= 58
Number of markers that Wesley sold in percent
= 100% - 10%
= 90%
90% =
90100 =
910 Make p the same.
(1) = (3)
58 - 10 u = 98 - 18 u
18 u - 10 u = 98 - 58
8 u = 40
1 u = 40 ÷ 8 = 5
Number of markers that Julian had left
= 58 - 10 u
= 58 - 10 x 5
= 58 - 50
= 8
Answer(s): 8
