Cody and Luis had 90 markers together. Luis had 6 less markers than Cody. Both of them sold some of their markers. Luis sold 25% more markers than what Cody sold. In the end, Luis had half as many markers left as Cody. How many markers had Luis left?
| |
Cody
(1) |
Luis
(2) |
Make p the same
(2)x2 = (3) |
Comparing Cody
and Luis at first |
6 more |
|
|
| Before |
48 |
42 |
84 |
| Change |
- 4 u |
- 5 u |
- 10 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Luis had at first
= (90 - 6) ÷ 2
= 84 ÷ 2
= 42
Number of markers that Cody had at first
= 42 + 6
= 48
Number of markers that Luis sold in percent
= 100% + 25%
= 125%
125% =
125100 =
54 Make p the same.
(1) = (3)
48 - 4 u = 84 - 10 u
10 u - 4 u = 84 - 48
6 u = 36
1 u = 36 ÷ 6 = 6
Number of markers that Luis had left
= 42 - 5 u
= 42 - 5 x 6
= 42 - 30
= 12
Answer(s): 12
