Sean and Oscar had 89 markers together. Sean had 25 more markers than Oscar. Both of them sold some of their markers. Oscar sold 40% less markers than what Sean sold. In the end, Oscar had half as many markers left as Sean. How many markers had Sean left?
| |
Sean
(1) |
Oscar
(2) |
Make p the same
(2)x2 = (3) |
Comparing Sean
and Oscar at first |
25 more |
|
|
| Before |
57 |
32 |
64 |
| Change |
- 5 u |
- 3 u |
- 6 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Oscar had at first
= (89 - 25) ÷ 2
= 64 ÷ 2
= 32
Number of markers that Sean had at first
= 32 + 25
= 57
Number of markers that Oscar sold in percent
= 100% - 40%
= 60%
60% =
60100 =
35 Make p the same.
(1) = (3)
57 - 5 u = 64 - 6 u
6 u - 5 u = 64 - 57
1 u = 7
1 u = 7 ÷ 1 = 7
Number of markers that Sean had left
= 57 - 5 u
= 57 - 5 x 7
= 57 - 35
= 22
Answer(s): 22
