Ian and Ahmad had 117 markers together. Ian had 21 more markers than Ahmad. Both of them sold some of their markers. Ahmad sold 20% less markers than what Ian sold. In the end, Ahmad had half as many markers left as Ian. How many markers had Ian left?
| |
Ian
(1) |
Ahmad
(2) |
Make p the same
(2)x2 = (3) |
Comparing Ian
and Ahmad at first |
21 more |
|
|
| Before |
69 |
48 |
96 |
| Change |
- 5 u |
- 4 u |
- 8 u |
| After |
2 p |
1 p |
2 p |
Number of markers that Ahmad had at first
= (117 - 21) ÷ 2
= 96 ÷ 2
= 48
Number of markers that Ian had at first
= 48 + 21
= 69
Number of markers that Ahmad sold in percent
= 100% - 20%
= 80%
80% =
80100 =
45 Make p the same.
(1) = (3)
69 - 5 u = 96 - 8 u
8 u - 5 u = 96 - 69
3 u = 27
1 u = 27 ÷ 3 = 9
Number of markers that Ian had left
= 69 - 5 u
= 69 - 5 x 9
= 69 - 45
= 24
Answer(s): 24
