Lee and Julian had 120 staplers together. Lee had 16 more staplers than Julian. Both of them sold some of their staplers. Julian sold 20% less staplers than what Lee sold. In the end, Julian had half as many staplers left as Lee. How many staplers had Lee left?
| |
Lee
(1) |
Julian
(2) |
Make p the same
(2)x2 = (3) |
Comparing Lee
and Julian at first |
16 more |
|
|
| Before |
68 |
52 |
104 |
| Change |
- 5 u |
- 4 u |
- 8 u |
| After |
2 p |
1 p |
2 p |
Number of staplers that Julian had at first
= (120 - 16) ÷ 2
= 104 ÷ 2
= 52
Number of staplers that Lee had at first
= 52 + 16
= 68
Number of staplers that Julian sold in percent
= 100% - 20%
= 80%
80% =
80100 =
45 Make p the same.
(1) = (3)
68 - 5 u = 104 - 8 u
8 u - 5 u = 104 - 68
3 u = 36
1 u = 36 ÷ 3 = 12
Number of staplers that Lee had left
= 68 - 5 u
= 68 - 5 x 12
= 68 - 60
= 8
Answer(s): 8
