Mark and Simon had 166 notebooks together. Mark had 34 more notebooks than Simon. Both of them sold some of their notebooks. Simon sold 30% less notebooks than what Mark sold. In the end, Simon had half as many notebooks left as Mark. How many notebooks had Mark left?
|
Mark (1) |
Simon (2) |
Make p the same (2)x2 = (3) |
Comparing Mark and Simon at first |
34 more |
|
|
Before |
100 |
66 |
132 |
Change |
- 10 u |
- 7 u |
- 14 u |
After |
2 p |
1 p |
2 p |
Number of notebooks that Simon had at first
= (166 - 34) ÷ 2
= 132 ÷ 2
= 66
Number of notebooks that Mark had at first
= 66 + 34
= 100
Number of notebooks that Simon sold in percent
= 100% - 30%
= 70%
70% =
70100 =
710 Make p the same.
(1) = (3)
100 - 10 u = 132 - 14 u
14 u - 10 u = 132 - 100
4 u = 32
1 u = 32 ÷ 4 = 8
Number of notebooks that Mark had left
= 100 - 10 u
= 100 - 10 x 8
= 100 - 80
= 20
Answer(s): 20