Will and Bryan had 45 pencils together. Bryan had 3 less pencils than Will. Both of them sold some of their pencils. Bryan sold 40% more pencils than what Will sold. In the end, Bryan had half as many pencils left as Will. How many pencils had Bryan left?
| |
Will
(1) |
Bryan
(2) |
Make p the same
(2)x2 = (3) |
Comparing Will
and Bryan at first |
3 more |
|
|
| Before |
24 |
21 |
42 |
| Change |
- 5 u |
- 7 u |
- 14 u |
| After |
2 p |
1 p |
2 p |
Number of pencils that Bryan had at first
= (45 - 3) ÷ 2
= 42 ÷ 2
= 21
Number of pencils that Will had at first
= 21 + 3
= 24
Number of pencils that Bryan sold in percent
= 100% + 40%
= 140%
140% =
140100 =
75 Make p the same.
(1) = (3)
24 - 5 u = 42 - 14 u
14 u - 5 u = 42 - 24
9 u = 18
1 u = 18 ÷ 9 = 2
Number of pencils that Bryan had left
= 21 - 7 u
= 21 - 7 x 2
= 21 - 14
= 7
Answer(s): 7
